Backpack with Value array:
note that: "Each item has different values and quantities."
function:
dp[i][j] |= dp[i - 1][j - A[i - 1] * k]; (when you take that ith item)
or
dp[i][j] = dp[i - 1][j]; (when you don't take that ith item)
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public class Solution { | |
/** | |
* @param n: the value from 1 - n | |
* @param value: the value of coins | |
* @param amount: the number of coins | |
* @return: how many different value | |
*/ | |
public int backPackVIII(int m, int[] A, int[] K) { | |
// write your code here | |
if (A == null || A.length == 0) { | |
return 0; | |
} | |
int n = A.length; | |
// init | |
boolean[][] dp = new boolean[n+1][m+1]; | |
dp[0][0] = true; | |
for (int j = 1; j <= m; j++) { | |
dp[0][j] = false; | |
} | |
// dp: functions | |
int counter = 0; | |
for (int i = 1; i <= n; i++) { | |
dp[i][0] = true; | |
for (int j = 1; j <= m; j++) { | |
dp[i][j] = dp[i - 1][j]; | |
for (int k = 1; k <= K[i - 1] && j - A[i - 1] * k >= 0; k++) { | |
dp[i][j] |= dp[i - 1][j - A[i - 1] * k]; | |
} | |
if (i == n && dp[i][j]) { | |
counter++; | |
} | |
} | |
} | |
// for (int i = 0; i <= n; i++) { | |
// System.out.println("Arrays.toString(dp[i]) = " + Arrays.toString(dp[i])); | |
// } | |
// dp: answer | |
return counter; | |
} | |
} |
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